I get
4*sqrt8-2*8=4*2sqrt2-16
can someone help me with this radical numbers problem?
(2suare root 8)(2-square root 8) would it be 2 square root 4?
2 answers
I have 2 interpretations of your problem:
1. (2 * sqrt 8) (2 * sqrt 8)
2. (2 * sqrt 8 ) (2 - sqrt 8)
I will solve both:
1. (2 * sqrt 8) (2 * sqrt 8) =
4 * 8 = 32.
2. (2 * sqrt 8) (2- sqrt 8) =
4 * sqrt 8 - 2 * 8 =
4 * sqrt (4*2) - 16 =
4 * 2 * sqrt 2 - 16 =
8 * sqrt 2 - 16 =
8(sqrt 2 - 2) = - 4.69.
1. (2 * sqrt 8) (2 * sqrt 8)
2. (2 * sqrt 8 ) (2 - sqrt 8)
I will solve both:
1. (2 * sqrt 8) (2 * sqrt 8) =
4 * 8 = 32.
2. (2 * sqrt 8) (2- sqrt 8) =
4 * sqrt 8 - 2 * 8 =
4 * sqrt (4*2) - 16 =
4 * 2 * sqrt 2 - 16 =
8 * sqrt 2 - 16 =
8(sqrt 2 - 2) = - 4.69.