I'm not quite sure of how much "estimation" the author wants but this is what I would do.
.......HSO4 ==> H^+ + SO4^2-
I......0.15.....0......0
C.......-x......x......x
E....0.15-x.....x......x
K2 for H2SO4 = (x)(x)/(0.15-x)
I would solve that exactly which will give a quadratic equation. Estimate the answer may mean to assume 0.15-x = 0.15
The difference in the two answers for (H^+) is about 15% so the term estimate may very well mean to assume 0.15-x = 0.15 to avoid the quadratic equation.
Then pH = -log(H^+).
Can someone help me with this question? This could help me with how to do another question, similar to this, for my homework.
1.Estimate the pH of
(a) 0.15 M NAHSO3 (aq)
(b) 0.050 M NaHSO3 (aq)
Thank you!
1 answer