A quick analysis and sketch of the curve will show x-intercepts at -4,0, and 4
Since you want the area from 0 to 4, it will be the region above the x-axis.
area =
⌠ 16x - x^3 dx from 0 to 4
⌡
= [8x^2 - 1/4x^4] from 0 to 4
= (8(16) - 1/4(256)) - 0
= 128-64
= 64
I find your statement "..I have no Idea how to do it" rather puzzling. This is a routine and quite simple problem in this topic, if you are studying Calculus
Can someone help me with this problem...I have no Idea how to do it.
Find the area between each curve and the x-axis for the given interval.
y=16x-x^3 from x=0 to x=4
Thanks for the help>>
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