Can someone help me with this equation:
y = (2*10^(-44))*(e^(0.055x))?
3 answers
If it helps, y = 50000.
The y = 50000 sure helps, without it it couldn't be done
so you want
(2*10^(-44))*(e^(0.055x)) = 50000
divide by that extremely small number
e^(0.055x) = 2.5*10^48
take ln of both sides and use log rules
.055x = ln (2.5*10^48)
.055x = 111.44
x = appr 2026.2
so you want
(2*10^(-44))*(e^(0.055x)) = 50000
divide by that extremely small number
e^(0.055x) = 2.5*10^48
take ln of both sides and use log rules
.055x = ln (2.5*10^48)
.055x = 111.44
x = appr 2026.2
If your expressiom mean:
y = 2 * 10 ^ ( - 44 ) * e ^ ( 0.055 x ) = 50000
then:
2 * 10 ^ ( - 44 ) * e ^ ( 0.055 x ) = 5 * 10 ^ 4 Divide both sides by 2 * 10 ^ ( - 44 )
e ^ ( 0.055 x ) = 5 * 10 ^ 4 / 2 * 10 ^ ( - 44 )
e ^ ( 0.055 x ) = ( 5 / 2 ) * 10 ^ 4 / 10 ^ ( - 44 )
e ^ ( 0.055 x ) = 2.5 * 10 ^ 4 * 10 ^ ( 44 )
e ^ ( 0.055 x ) = 2.5 * 10 ^ 48 Take the natural logarithm of both sides
0.055 x = 111.4403752 Divide both sides by 0.055
x = 111.4403752 / 0.055
x = 2026.18864
y = 2 * 10 ^ ( - 44 ) * e ^ ( 0.055 x ) = 50000
then:
2 * 10 ^ ( - 44 ) * e ^ ( 0.055 x ) = 5 * 10 ^ 4 Divide both sides by 2 * 10 ^ ( - 44 )
e ^ ( 0.055 x ) = 5 * 10 ^ 4 / 2 * 10 ^ ( - 44 )
e ^ ( 0.055 x ) = ( 5 / 2 ) * 10 ^ 4 / 10 ^ ( - 44 )
e ^ ( 0.055 x ) = 2.5 * 10 ^ 4 * 10 ^ ( 44 )
e ^ ( 0.055 x ) = 2.5 * 10 ^ 48 Take the natural logarithm of both sides
0.055 x = 111.4403752 Divide both sides by 0.055
x = 111.4403752 / 0.055
x = 2026.18864