Question

Can someone help me with this equation:

y = (2*10^(-44))*(e^(0.055x))?

Answer 1

If it helps, y = 50000.

Answer 2

The y = 50000 sure helps, without it it couldn't be done

so you want
(2*10^(-44))*(e^(0.055x)) = 50000
divide by that extremely small number
e^(0.055x) = 2.5*10^48
take ln of both sides and use log rules
.055x = ln (2.5*10^48)
.055x = 111.44
x = appr 2026.2

Answer 3

If your expressiom mean:

y = 2 * 10 ^ ( - 44 ) * e ^ ( 0.055 x ) = 50000

then:

2 * 10 ^ ( - 44 ) * e ^ ( 0.055 x ) = 5 * 10 ^ 4 Divide both sides by 2 * 10 ^ ( - 44 )

e ^ ( 0.055 x ) = 5 * 10 ^ 4 / 2 * 10 ^ ( - 44 )

e ^ ( 0.055 x ) = ( 5 / 2 ) * 10 ^ 4 / 10 ^ ( - 44 )

e ^ ( 0.055 x ) = 2.5 * 10 ^ 4 * 10 ^ ( 44 )

e ^ ( 0.055 x ) = 2.5 * 10 ^ 48 Take the natural logarithm of both sides

0.055 x = 111.4403752 Divide both sides by 0.055

x = 111.4403752 / 0.055

x = 2026.18864