Asked by Aryaa

Can someone help me with the following?

Prove that (grad)^2 f(r) = D^2/dr^2 + (2/r) Df/Dr



Where D^2/dr^2 refers to the second partial derivative of f , w.r.t. r and



Df/ Dr refers to partial derivative of f, w.r.t r



vector r = xi + yj + zk and f(r) is twice differentiable


My work so far :

Definition of grad^2 : (grad)^2 f = fxx+fyy+fzz where the subscripts mean partial derivatives.

For example, fx=∂f/∂x.


r2=x2+y2+z2, so taking partial derivatives of both sides ...

2rrx=2x => rx=x/r and likewise ry=y/r and rz=z/r


Answers

Answered by oobleck
what is "D^2/dr^2" ?
It looks like an operator, but ∇<sup><sup>2</sup></sup>f is not just an operator. Did you mean D^2f/dr^2 ?
Answered by Aryaa
Yes, D^2f/dr^2 , thats what I meant there?
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