cos(180-x) = -cos(x)
cos(90-x) = sin(x)
so you have
(0.5)cos^2(x)sin^2(x) = 0.05
cos^2(x) sin^2(x) = 1/10
sin^2(2x) = 1/40
sin(2x) = ±1/(2√10)
...
can someone help me solve for x for this equation
(0.5)(((cos(180-x))^(2))(cos(90-x))^(2))=0.0500
1 answer