Can someone give me some directions as to how to reach the answer for this problem:
A 0.608g sample of fertilizer contained nitrogen as ammonium sulfate,
(NH4)2 SO4(s)+2NaOH(aq)-->Na2SO4(aq)+ 2H2O(l)+2NH3(g)
The ammonia was collected in 46.3 mL of 0.213 M HCL (hydrochloric acid), with which it reacted.
NH3(g)+HCL(aq)-->NH4Cl(aq)
This solution was titrated for excess hydrochloric acid with 44.3 mL of 0.128 M NaOH
NaOH(aq)+HCL(aq)NaCL(aq)+H2O(l)
What is the percentage of nitrogen in the fertilizer?
The answer is 9.66%
1 answer
I get 9.86 something...