Can someone explain to me how to find the equation pf the line in the form Ax + By + C =0 if
a) parallel to x=3 and passes through (-4, 3)
b)perpendicular to y=4 and passes through (1, 1)
c) passes through the x-int of y=2x-6 and y-int of y=-3x+6
If it is parallel to x=3, the slope is undefined (vertical line), so it is an x=constant, in this case, x=-4
A=1, B=0, C=4
If it is perpendicular to y=4, then it is a vertical line. X=1
A=1 B=0, C=-1
2*3
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