I assume you mean
∫ cos(x)/√(sinx) dx
let u^2 = sinx
2u du = cosx dx
Now the integral is
∫ 2u/u du = 2∫du
= 2u+c
= 2√(sinx)+c
Can someone explain how
cos(X)/ square root (sin (X))
is 2 square root sin(x) +c
Thanks!
1 answer