Can someone correct these for me.PLZ

Question

Problem#1
Directions solve equation
�ãx+4 = 3

My answer: x = 5

Probelm #2
Directions solve equation

�ã(4x+1) + 3 = 0

My answer x = 2

Problem #3
Directions solve equation
�ã(2y+7)+4=y
My answer y= 1 and y = 9

the symbol a is a radical it came out wrong.

the first one is correct
Use brackets to show which parts are below the square root sign

in the second:
√(4x+1)+3=0
√(4x+1)=-3
square both sides etc.

You should have been told that if you obtain algebraic answers after "squaring" , all solutions have to be verfied.
If you check your answer of x=2, it does not satisfy the original equation.
So the second equation has no real solution.

The same is true for your third equation.
Even though y=1 and y=9 are algebraic solutions, when you check the answers in the original equation, only y=9 works, the other answer is not valid.