Can someone correct me if I trypedthese incorrectly andslolve them PLEASE
5/(y-2)=y+2
(x/3)-(2/3)=(1/y-5)
(y+2)/7=1(y-5)
(x^2)/(x-4)-7/(x-4)=0
x^2/(x+3)-5/(x+3)=0
5/(y-2)=y+2
(x/3)-(2/3)=(1/y-5)
(y+2)/7=1(y-5)
(x^2)/(x-4)-7/(x-4)=0
x^2/(x+3)-5/(x+3)=0