Asked by dee
can someone check me and see if this is correct.
ã(4x+1) + 3 = 0
ã(4x+1)= -3
ã(4x+1).2= -3.2
4x + 1 = 9
4x = 9 - 1
4x = 8
x = -2
not sure what your symbol ã means but it appears like you mean square root.
If that is the case then in your second line
√(4x+1)= -3 you could stop, since by definition the square root symbol says to take the positive square root of a number.
So it could not be a negative.
Your solution would be:
No solution in the real number set
ã(4x+1) + 3 = 0
ã(4x+1)= -3
ã(4x+1).2= -3.2
4x + 1 = 9
4x = 9 - 1
4x = 8
x = -2
not sure what your symbol ã means but it appears like you mean square root.
If that is the case then in your second line
√(4x+1)= -3 you could stop, since by definition the square root symbol says to take the positive square root of a number.
So it could not be a negative.
Your solution would be:
No solution in the real number set
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