Asked by Anonymous
can someone also help me ndertsand this question ; y=x^3 +2x^2+3 represents the rate of an object over the interval [7, 10]. What is the average rate of the object over the time interval?
Answers
Answered by
Damon
find y at the end (x = 10)
find y at the beginning (x=3)
subtract
Yend - Ybegin
divide that by 10-7 which is 3
find y at the beginning (x=3)
subtract
Yend - Ybegin
divide that by 10-7 which is 3
Answered by
Steve
actually, the above solution applies if y is the position function. Since it is itself a rate, you need the average value of the function. That is
∫[7,10] x^3+2x^2+3 dx
----------------------------- = 782.25
10-7
∫[7,10] x^3+2x^2+3 dx
----------------------------- = 782.25
10-7
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