Eq1. Given: (x - 2) (x - 3) < 0.
Eq2. Graph (x - 2) (x - 3) = 0,
x - 2 = 0,
x = 2 = x-Int.
x - 3 = 0,
x = 3 = x-Int.
Find the coordinates of the vertex:
h = Ave of the x-Ints,
h = Xv = (2 + 3) / 2 = 2.5.
Substitute 2.5 for x in Eq2 to get
y coordinate of vertex:
k = Yv = (2.5 - 2) (2.5 - 3) = -0.25.
V(h , k) = V(2.5 , -0.25).
Use the coordinates of the vertex and x-ints to sketch the graph:
(2 , 0) , V(2.5 , -0.25) , (3 , 0).
Your inequality uses the < sign.
So all points on the graph between the
X-Ints are negative(less than 0) and
satisfy the inequality.
In Eq form: 2 < X < 3.
The Eq states that all values of x >
2 but < 3 satisfy the inequality.
can somebody tell me how to solve this inequality equation?
(a-2)(a-3)<0
I know the opposite was 2 and 3..but how do i determine the greater than, less than or equal to? Explain please.
2 answers
You can use the letter a as your variable if you desire. I didn't mean to use x.
1 answer