Can somebody shows me step by step with numbers on how to calculate the period for this question-equation. A black hole is an object with mass, but no spatial extent. It truly is a particle. A black hole may form from a dead star. Such a black hole has a mass several times the mass of the Sun. Imagine a black hole whose mass is eighty-two times the mass of the Sun.Use the equation T^2=((4π^2)/GM)a^3 to calculate this period.

Question

Can somebody shows me step by step with numbers on how to calculate the period for this question-equation. A black hole is an object with mass, but no spatial extent. It truly is a particle. A black hole may form from a dead star. Such a black hole has a mass several times the mass of the Sun. Imagine a black hole whose mass is eighty-two times the mass of the Sun.Use the equation T^2=((4π^2)/GM)a^3 to calculate this period. 
 I think this is Kepler third law equation.

Steve · Answer

well, it looks like M is 82*sunmass find the values for that and G and a and then just plug them in. I assume you can do that much...

joy · Answer

do you know what is a equal to. I know everything else except for a.

Steve · Answer

clearly you did not make the effort to look up the law. a is the semi-major axis of the elliptical orbit.

joy · Answer

i still don't know what the value for a is.I look up on google and it is the distance in AU and this question doesn't give what is the value for a.

Dr. Neutron · Answer

You use the wrong equation. Use this equation square root (a^3/M) and you will get the answeranswer equal to .110yr ais1 and M is 82kg