Can somebody show I how to use the three equations to get the same answer for Tac and Tad? Answer for Tac=16.9 and for Tad=35.9. Please show steps so I understand.
eq1 0Tab+ -.5Tac+0.5Tad+0Wa=0
eq2 .707Tab+ -.75Tac+.75Tad+0Wa=0
eq3 .707Tab+.433Tac+.433Tad-1Wa=0
5 answers
typo. It is for tab and Tac not Tad.Tab=35.9 and Tac=16.9
Rather than those tacky Ta* names, I'll just call them b,c,d
And what is that Wa name supposed to be? You say that the Ta* variables have numeric values, but that's not possible if there's a Wa variable floating about. Is that supposed to be just another name? I'll call it a. Then we have
(#1) 0b - .5c + 0.5d = 0
(#2) .707b - .75c + .75d = 0
(#3) .707b + .433c + .433d = 1
Those look suspiciously like sines and cosines. Is this some kind of rotation mattix? Anyway, since you want numeric values for b,c,d, I'll let a=1.
Subtracting #2 from #3, we are left with
(#1) -.5c + 0.5d = 0
(#4) 1.183c - 0.317d = 1
Sine #1 says that c = d, we are left with
0.866d = 1
d = 1/.866 = 2/√3
Ahhh! Now I see that Tad is supposed to mean tan(d). Why didn't you say so?
tan 40.9° = 2/√3
I do not know how you got the values you did.
I still don't know what trig function W is supposed to be, but the key to doing this is just solving as any other 3x3 matrix, for which there are numerous online calculators. In any case, once you have a value for Tac, then c = arctan(Tac)
And what is that Wa name supposed to be? You say that the Ta* variables have numeric values, but that's not possible if there's a Wa variable floating about. Is that supposed to be just another name? I'll call it a. Then we have
(#1) 0b - .5c + 0.5d = 0
(#2) .707b - .75c + .75d = 0
(#3) .707b + .433c + .433d = 1
Those look suspiciously like sines and cosines. Is this some kind of rotation mattix? Anyway, since you want numeric values for b,c,d, I'll let a=1.
Subtracting #2 from #3, we are left with
(#1) -.5c + 0.5d = 0
(#4) 1.183c - 0.317d = 1
Sine #1 says that c = d, we are left with
0.866d = 1
d = 1/.866 = 2/√3
Ahhh! Now I see that Tad is supposed to mean tan(d). Why didn't you say so?
tan 40.9° = 2/√3
I do not know how you got the values you did.
I still don't know what trig function W is supposed to be, but the key to doing this is just solving as any other 3x3 matrix, for which there are numerous online calculators. In any case, once you have a value for Tac, then c = arctan(Tac)
Wa=40
Canyou show I how the matrix will like because I confuse on how to enter it on the trix calculator. If you can post the site below so I can get to it and see. I have nver use a matrix calculator before.
no idea, but surely you just enter the numbers and tell it to solve the matrix. If it's any good, it will have examples. I know wolframalpha.com solves matrices, in several ways. It has helpful examples of the syntax to use.
There are also Gauss-Jordan elimination solvers you can use. google will provide several web sites.
There are also Gauss-Jordan elimination solvers you can use. google will provide several web sites.
0 answers