Can somebody please help me with these problems?
Factor the expression on the left side of each equation. Then solve.
1)x^4-5x^2+4=0
2)x^4-8x^2+16=0
Please and thank you!
1) let y = x^2, then
y^2-5y+4=0
(y-4)(y-1)=0
y = 4 or y = 1
x^2 = 4 or x^2 = 1
x = -2, +2, -1, +1
same approach for #2
So the factored form would be (y-4) (y-1) and the solutions would be -2, 2, -2, and 1?
We learned that you were supposed to do it like this:
x^4-5x^2+4=0
(x^2)^2-5(x^2)+4
a^2-2a+4...and then factor it and I'm not quite sure how to do that. Does it make any sense to you?
Okay, I'm Valerie by the way. Actually, I'm Linda and Valerie. But actually, I'm neither. I just always change my name. Sorry about that.