can some one tell me the simplified cube radical form of (64x^5y^7)^1/3

Answer 1

Hi Roger,

For this problem, you have to cuberoot each of the element (64, x^5 & y^7) separately.

For 64 , cuberoot of 64 is 4.
x^5 , cuberoot is x^(5/3)
y^7, the cuberoot is y^(7/3)

Therefore the simplified cube radical form is 4x^(5/3)y^(7/3)

Hope this helps you

Answer 2

Please don't switch names
I replied to you when you posted this earlier under a different name.
Did you not look at the reply before reposting?

http://www.jiskha.com/display.cgi?id=1381327293

btw, in your posting as Kim, you had x^3 instead of the current x^5