You definitely will need brackets to establish the order of operation
I will assume you mean
lim (2x^-1 + 3x)/(x + 4x^-1) as x ---> 0
if so, then ....
= lim (2 + 3x^2)/(x^2 + 4) as x ---> 0 , I multiplied top and bottom by x
= 2/4
= 1/2
Can i ask something is the answer in
lim 2x^-1+3x/x+4x^-1
x-0
is infinity?
1 answer