can anyone offer advice to find ƒÆmax after one has found that cosƒÆmax=[�ã(1+15ƒÀ2)+1]/3ƒÀ ?
I do not really understand the approximation given where ƒÀ=1-ƒÃ
Thanks
Sorry
Į ----> theta
ã -----> square root
ƒÀ -----> beta
ƒÃ - ----> E
rewritten... Sorry about the confusion!
can anyone offer advice to find (theta)max after one has found that cos(theta)max=[�sqrt(1+15beta^2)+1]/3beta ?
I do not really understand the approximation given where beta=1-E
Thanks