X^2+5aX+6a^2
splitting the middle term as
X^2+3ax+2aX+6ax^2
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take common factor from 2 terms,sequentially as
X(X+3a)+2a(X+3a)
(X+2a) (X+3a) answer is x=-2a ;X=-3a
Question 2: a^2+a-20=0
a^2+5a-4a-20=0
a(a+5)-4(a+5)
(a+5) (a-4)=0
or a=-5 ; +4
both are factorised using splitting the middle term method
Can anyone help me understand how to do this?
Factoring each polynomial
x^2+5ax+6a^2
and
solve each equation
a^2+a=20
I am so lost with this one I can not grab how you get a number from this.
thanks for trying who ever you may be
1 answer