Question

Camille buys a cake for $\$24.99$$24.99​ . She also buys $12$12​ brownies. Each brownie costs the same amount. She spends $\$39.99$$39.99​ on the cake and the brownies.

Camille finds the cost of each brownie by calculating $(39.99\ -\ 24.99)\ \div\ 12$(39.99 − 24.99) ÷ 12​ . Tanya finds the cost of each brownie by solving the equation $39.99\ +\ 12b\ =\ 24.99$39.99 + 12b = 24.99​ , where $b$b​ is the cost of each brownie.

Which approach uses the sequence of operations necessary to find the cost of each brownie: Camille’s, Tanya’s, both, or neither? Explain why.

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