cameron is making bead necklaces. he has 90 green beads and 108 blue beads. what's the greatest number of identical necklace he can make if he wants to use all the beads

Answer 1

assuming, the 90 green and 108 blue are indistinguishable,
number of arrangements
= 198!/(90!108!)

( which is the same as C(198,108) , too large for my calculator to hold that number. )

Am I misinterpreting the question?

Answer 2

18

Answer 3

I hAt Mo MaTh GoDtHeHeCk