To solve this problem, we need to understand the growth of the investment over time according to the provided exponential growth model:
\[ a(t) = 1,000(1.09)^t \]
Here, \( a(t) \) represents the amount of money in the account after \( t \) years, with the initial amount of $1,000 and an annual interest rate of 9%.
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Graph Behavior: The function \( a(t) \) is an exponential growth function because the base (1.09) is greater than 1. This means that the amount will increase over time.
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10 Years Later: We are specifically interested in the amount after 10 years: \[ a(10) = 1,000(1.09)^{10} \] Calculating \( (1.09)^{10} \): \[ (1.09)^{10} \approx 2.3679 \quad (\text{using a calculator for precision}) \] Now plugging that back into the equation: \[ a(10) \approx 1,000 \times 2.3679 \approx 2,367.90 \]
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Choosing the Right Graph:
- The first graph is an increasing curve which is likely to be correct as the function models exponential growth.
- The second graph is a decreasing curve, which does not match our function as \( a(t) \) is not decreasing.
- The third graph is described as another increasing curve, implying it's possible as well (assuming it closely aligns with the function).
Based on our calculations and understanding of the function's growth behavior, the correct graph should be the one that shows an increasing curve as \( t \) progresses, confirming that the amount in the account is indeed growing over time, especially around the 10-year mark.
Given that we don't have the images, I recommend you look for the first or third image that shows an increasing curve. The first graph seems likely to accurately represent the situation if it corresponds to the rise in the amount of money over time.