Calian wants to construct a viable argument to justify that logbb=1

Question

 for  b>0
 and  b≠1
. Fill in the blanks to help him construct his argument.(2 points)
Any positive number raised to the power  is equal to itself. Written as an equation, this means that $$ for any positive base. This equation is equivalent to the logarithmic equation $$. Therefore, it must be true that logbb=1
 for any positive base that is not equal to 1.

Answer 1

b^1 = b

b^x = b

x = 1

log_b (b) = 1