Not sure what all those m's and s's are, but I'll assume they're just units (which make no sense as written), and
x(t) = 2.17 + 4.80t^2 - 0.10t^6
v(t) = dx/dt = 9.60t - 0.600t^5
So, v=0 when t = 0 or t=2
And, of course, a(t) = 9.6 - 3.00t^4
So plug in your t values as needed.
Calculus Based (Projectile)
The position of the front bumper of a test car under microprocessor control is given by x(t)=2.17m+(4.80m/s^2)t^2•-(0.100m/s^6)t^6. Find the position and the acceleration at the instants when the car has zero velocity.
Please help meeee.
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