calculating the molarity of acetic acid in a vinegar sample given that 5.00 of vinegar required 43.50 mL of 0.1050 M NaOH to just reach the methyl red endpoint.

Answer 1

Is that 5.00 mL )0.00500L)vinegar?
mols NaOH = M x L = ?
Then M = mols/L soln