You don't have a balanced equation.
mols Sn = grams/atomic mass = ?
mols H2 = mols Sn
Use PV = nRT and solve for volume.
Calculate the work, in kJ, done when 126 g of tin dissolves in excess acid at 25.0˚C and 1.00 atm. Assume Ideal Gas behavior. Sn(s) + 2 H+(aq) → Sn2+(aq) + H2(g)
I basically need to know how to find the change in volume since work=-pressure*volume change and I have pressure already. Thanks!
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