Calculate the work done by the effort and the effort applied when a system of 6polley is used to raise a load of 600N through a distance of 30m. The work done against friction is 2000J.

Answer 1

total effort work ... [6 * 30 m * (600 / 6) N] + 2000J = 20000 J

effort distance ... 6 * 30 m = 180 m

effort applied = 20000 J / 180 m = ? N

Answer 2

20180