Calculate the volume of solution that has a vapour pressure of 25.8 mbar and contains 200.3 g of galactose, C6H12O6, at a temperature of 22.0 °C. The vapour pressure of pure water at 22 °C is 26.40 mbar, the density of water is 1.00 g mL-1, and assume no change in volume occurs upon

Question

Calculate the volume of solution that has a vapour pressure of 25.8 mbar and contains 200.3 g of galactose, C6H12O6, at a temperature of 22.0 °C. The vapour pressure of pure water at 22 °C is 26.40 mbar, the density of water is 1.00 g mL-1, and assume no change in volume occurs upon
dissolution.

huehue · Accepted Answer

Assuming this is from MasteringChemistry, the correct answer is 862 mL.

DrBob222 · Answer

mols galactose = 200.3/180 = approx 1.1

Psoln = XH2O*PoH2O
25.8 = XH2O*26.4
Solve for XH2O
1-XH2O = Xgal

Xgal=ngal/(ngal+nH2O)
Solve for nH2O

nH2O = grams/molar mass H2O
Solv for grams. Convert g to volume using density.