Write and balance the equation.
C6H12O6 + 6O2 ==> 6CO2 + 6H2O
mols glucose = grams/molar mass = ?
Using the coefficients in the balanced equation, convert mols glucose to mols O2.
Now convert mols O2 to volume (L) using PV = nRT and the conditions listed.
Calculate the volume of oxygen you would need, at 1.00 atm and 298 K, to completely oxidize 51g of glucose.
1 answer
1 answer