Calculate the volume of oxygen at STP required to burn 3.7 kg C3H6O2 producing CO2 & H2O:

Answer 1

balance the equation

O2 + C3H6O2 >> CO2 + H20

then convert 3.7kg to moles of C3H6O2, I assume you can do that.

Now from the balanced coefficents, you know how many moles of O2 was needed, then convert moles to stp volume.