calculate the volume of hydrogen produced from .025g of aluminum and sufficient HCl at 21 degrees Celsius and 755 torr according to the following reaction:

Question

Al(s) + HCl(aq)--------- AlCl3 (aq) + H2(g)

Volume of H2________ml

Answer 1

2Al + 6HCl ==> 2AlCl3 + 3H2
mols Al = grams/molar mass
Using the coefficients in the balanced equation, convert mols Al to mols H2.
Then use PV = nRT and convert mols H2 to L at the conditions listed. Change L to mL.