Calculate the volume of Co2 that would be produced from 0.5 mole of Fe2O3 according to the following equation

Answer 1

The balanced chemical equation for the reaction of Fe2O3 with CO is:

Fe2O3(s) + 3CO(g) -> 2Fe(s) + 3CO2(g)

According to the equation, 3 moles of CO are required to produce 3 moles of CO2. Therefore, 1 mole of CO produces 1 mole of CO2.

Given that 0.5 moles of Fe2O3 react with CO, we can calculate the volume of CO2 produced using the ideal gas law:

n = PV / RT

Where:
n = moles of CO2
P = pressure (assume 1 atm)
V = volume of gas
R = ideal gas constant (0.0821 L*atm/mol*K)
T = temperature (assume room temperature, 298 K)

Convert moles of Fe2O3 to moles of CO2:
0.5 moles of Fe2O3 * (3 moles of CO2 / 1 mole of Fe2O3) = 1.5 moles of CO2

Now, substitute the values into the equation:

1.5 moles = (1 atm) * V / (0.0821 L*atm/mol*K * 298 K)

V = (1.5 moles * 0.0821 L*atm/mol*K * 298 K) / 1 atm
V ≈ 36.9 L

Therefore, 0.5 moles of Fe2O3 would produce 36.9 L of CO2 gas.