Calculate the volume of CO2 produced at S.t.p when 25cm3 of 0.25mol/dm3 Hcl reacts with Na2Co3.

Answer 1

balance the equation:
Na2CO3 +2 HCl >>> 2NaCl+ H2O + CO2

moles HCl: .25*25/1000=6.25e-3 moles
so according to the equation above, it will react with half that sodium carbonate.
Moles Na2CO3; volume/22.4 = 1/2 * .625e-4
volume=22.4*.5*.625e-e dm^3

Answer 2

Don't understand