N2 + 3H2 -> 2NH3
140g N2 = 5 moles
30g H2 = 15 moles
So, you will get 10 moles NH3
1 mole occupies 22.4 L, so ...
Calculate the volume of amonia gas is produced at STP when 140g of nitrogen gas reacts with 30g of hydrogen gas (Atomic mass N=14u,H=1u)
1 answer