2,180 ppm = 2,180 mg Pb(NO3)2/L soln = 2.18 g Pb(NO3)2/L soln
moles Pb(NO3)2 = 2.18/molar mass Pb(NO3)2 = about 0.0066 M.
Then use c1v1 = c2v2 to see how much to dilute this solution.
This calculation is based on the density of the 2180 ppm soln being 1.00 g/mL.
Calculate the volume of 2,180 ppm Pb(NO3)2 solution required to prepare 1.2550 L of a 0.0021 M Pb2+ solution.
3 answers
how would i use 2180 as a c1 or c2?
To use my approximate values.
c2 = 0.0021 M soln you want
v2 = 1.2550 L soln you want
c1 = 0.0066 M soln you have
V1 = ? = want to know this
c2 = 0.0021 M soln you want
v2 = 1.2550 L soln you want
c1 = 0.0066 M soln you have
V1 = ? = want to know this