Calculate the volume of 1.86M Na3PO4 solution that can be prepared from 5.45 g of Na3PO4

Answer 1

Moles of Na3PO4 = 5.45 g/molar mass of Na3PO4 g/mol

Let the volume of the Na3PO4 solution be=v dm^3

1.86 mol/dm^3 * v dm^3 = moles of Na3PO4

Hope this helps..