How much NH3 do you have? That is mols = M x L = ?
Look at the coefficients in the balanced equation. It takes 1/2 as much H2SO4. So mols H2SO4 = 1/2 mols NH3.
M H2SO4 = mols H2SO4/L H2SO4.
You know M and mols, solve for L.
Calculate the volume of 1.78M sulfuric acid that would be needed to neutralize 62.4 mL of a 2.09 M aqueous ammonia solution. The equation for the reaction is
H2SO4(aq) + 2 NH3(aq) ---> 2 NH4(aq)+ SO4
^-2 (aq)
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