I've corrected the equation.
2H3PO4 +3Mg(OH)2 ==> Mg3(PO4)2 + 6H20
mols Mg(OH)2 = M x L = ?
Convert mols Mg(OH)2 to mols H3PO4 using the coefficients in the balanced equation.
Then mols H3PO4 = M H3PO4 x L H3PO4 You know mols and M, solve for L.
calculate the volume of 1.07M phosphoric acid solution necessary to react with 22.9 ml of 0.150M Mg(OH)
2H3PO4 +3Mg(OH)2 ==> Mg(PO4)2 + 6H20
1 answer
1 answer