M1 x mL1 = M2 x mL2
0.01 x mL1 = 5E-4 x 100
Solve for mL1 = ?. Let's say, for the fun of it that is 5 mL.
Then one proceeds by placing 5 mL of the 0.01 M CuSO4 into a 100 mL volumetric flask, then adding distilled water up to the mark. Mix thoroughly stopper, label. My point in writing this last part is to make sure you don't think you take 5 mL of the 0.01 M CuSO4 solution and add 100 mL of distilled H2O because then you will have more than 100 mL total. Also note that you don't add 95 mL water. By doing it the way I have written it means you add 5 mL of the 0.01 M CuSO4 and enough water to make it to the mark for a TOTAL volume of 100. That means you added approximately 95 mL distilled water.
Calculate the volume of 0.010 M CuSO 4 solution needed to make 100 mL of a 5.0 10 ^ - 4 CuSO 4 solution .
1 answer
1 answer