Calculate the volume (mL) of the solute (CH3)2CO and the volume (L) of the solvent H2O that should be added to prepare 1.36 kg of a solution that is 25.7 g (CH3)2CO per 100. g solution.
Molar Mass (g/mol)
(CH3)2CO 58.05
H2O 18.015
Density (g/mL):
(CH3)2CO 0.7899
H2O 0.9982
Name/Formula:
acetone
(CH3)2CO
water
H2O
2 answers
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You want 25.7 g ac/100 g soln.
You want 1.36 kg solution or 1360 g.
1359 g soln x (25.7 g Ac/100 g soln) = ?? g acetone.
Or set up a ratio/proportion
(25.7 ac/100 g soln) = (x g ac/1360 g soln) and solving for x gives ?? (should be the same answer but try it and see).
Check it. I think about 349 g acetone but you need to do it more accurately that my estimate).
349 solute/1360 g soln = 0.2567 g/g or 25.7 g/100.
You want 1.36 kg solution or 1360 g.
1359 g soln x (25.7 g Ac/100 g soln) = ?? g acetone.
Or set up a ratio/proportion
(25.7 ac/100 g soln) = (x g ac/1360 g soln) and solving for x gives ?? (should be the same answer but try it and see).
Check it. I think about 349 g acetone but you need to do it more accurately that my estimate).
349 solute/1360 g soln = 0.2567 g/g or 25.7 g/100.
5 answers