[12.5g of CaCO3*(1 mole/100.09g)/(0.12M)]*(10^3mL/L)=????? <==== two significant figures.
(0.850 moles/0.500M)*(10^3mL/L)=???? <===== three significant figures
Calculate the volume in ml of:
a. 12.5 g of calcium carbonate from a 0.12 M solution
b. 0.850 moles of sodium nitrate from a 0.500 M solution
1 answer