Calculate the volume (in mL) of 9.0M H2SO4 that you would need to convert 0.070 moles of KAl(OH)4 to K2SO4 and Al2(SO4)3 according to the following equation:

Question

Calculate the volume (in mL) of 9.0M H2SO4 that you would need to convert 0.070 moles of KAl(OH)4 to K2SO4 and Al2(SO4)3 according to the following equation:
2 KAl(OH)4 + 4 H2SO4->K2SO4 + Al2(SO4)3 + 8 H2O

DrBob222 · Answer

Follow the same procedure as for the alum problems. You may need an additional formula that is M = moles/L for the H2SO4.

jaykey · Answer

.07moleKAL(oh4)*2mole(h2so4)/9mole(h2so4)=15.6mlH2So4