Calculate the volume in milliliters of a 0.46M sodium carbonate solution that contains 25.0 g of sodium carbonate (Na2CO3). Be sure your answer h correct number of significant digits.

Answer 1

To calculate the volume of the solution, we first need to determine the number of moles of sodium carbonate in 25.0 g.

The molar mass of Na2CO3 is:
Na: 22.98977 g/mol * 2 = 45.97954 g/mol
C: 12.0107 g/mol
O: 15.9994 g/mol * 3 = 47.9982 g/mol

Total molar mass = 45.97954 + 12.0107 + 47.9982 = 105.98844 g/mol

Number of moles of Na2CO3 = 25.0 g / 105.98844 g/mol = 0.236 mols

Now, we can use the molarity formula to calculate the volume of the solution:
Molarity (M) = moles of solute / volume of solution (in liters)

0.46 M = 0.236 mol / volume (in liters)

Volume (in liters) = 0.236 mol / 0.46 mol/L = 0.513 L

Finally, we convert the volume to milliliters by multiplying by 1000:
Volume (in milliliters) = 0.513 L * 1000 mL/L = 513 mL

Therefore, the volume of the 0.46M sodium carbonate solution that contains 25.0 g of Na2CO3 is 513 milliliters.