Calculate the volume in liters of a 0.00228 mM calcium sulfate solution that contains 425. mmol of calcium sulfate (CaSO,). Be sure your answer has the correct number of significant digits.

Answer 1

1. First, we need to calculate the number of moles of CaSO4 in the solution:

Number of moles = 425 mmol = 0.425 mol

2. Next, we need to calculate the volume of the solution using the molarity formula:

Molarity = moles of solute / volume of solution (in liters)
0.00228 mM = 0.00000228 mol/L

Volume of solution = moles of solute / molarity
Volume = 0.425 mol / 0.00000228 mol/L
Volume = 186,403.51 L

3. Finally, we convert the volume from liters to mL (1 L = 1000 mL):

Volume = 186,403.51 L x 1000 mL/L
Volume = 186,403,510 mL

Therefore, the volume of the 0.00228 mM calcium sulfate solution that contains 425. mmol of CaSO4 is 186,403,510 mL or 1.86 x 10^8 mL with the correct number of significant digits.