The kinetic energy will be the work done on the proton which is the charge times the voltage. Since the charge on the proton is the same magnitude as on the electron, 2.7 volts should do the trick.
then (1/2) (1.67*10^-27) v^2 = 2.7(1.6*10^-19 Joules/eV)
Calculate the voltage required to accelerate a beam of protons initially at rest if they have a kinetic energy of 2.7 eV.
deltaV = V
Calculate their speed if they have a kinetic energy of 2.7 eV .
v = m/s
1 answer
1 answer