Fgravity=Fcentripetal
GMearth/(radEarth+ 2600km)^2= mv^2/(radearth+2600)
solve for v.
change all distances to meters..
Calculate the velocity of a satellite moving in a stable circular orbit about the Earth at a height of 2600 km.
5 answers
would m be the mass of the earth?
m is mass satellite.
And I forgot one on the left of that line.
Here is is corrected:
GMearth*m/(radEarth+ 2600km)^2= mv^2/(radearth+2600)
And I forgot one on the left of that line.
Here is is corrected:
GMearth*m/(radEarth+ 2600km)^2= mv^2/(radearth+2600)
does that mean the mass of the statellite cancels? because the mass of the statellite isnt given
yes, the mass of the satellite divides out.