Calculate the value of a, A and C in ∆Abc given that b = 17.23cm, c= 10.86cm and B= 101°15

Answer 1

use the law of sines.
sinC/c = sinB/b
sinC/10.86 = sin101°15'/17.23
C = 38.18°
unless you meant C=101.15°, in which case you need to adjust this result.
Then it is easy to find A, since A+B+C=180°
Then, using the law of sines again, a/sinA = b/sinB
or, using the law of cosines, a^2 = b^2+c^2 - 2bc cosA

Answer 2

Using the law of cosine