Calculate the total number of moles of gas produced from the decomposition of 10.0 g of guanidinium nitrate

Question

I know that the equation for the decomposition is CH6N4O3 (s) → 3 H2O (g) + 2 N2 (g) + C but I don't know where to go from here.

Answer 1

figure the moles of CH6N4O3 in 10.0g
The equation says that you will get 5 times that many moles of gas (3H2O and 2N2)

Answer 2

mol of CH6N4O3 is 12+6+(4*14)+(3*16) grams